Problem:
 1(2(1(x1))) -> 2(0(2(x1)))
 0(2(1(x1))) -> 1(0(2(x1)))
 L(2(1(x1))) -> L(1(0(2(x1))))
 1(2(0(x1))) -> 2(0(1(x1)))
 1(2(R(x1))) -> 2(0(1(R(x1))))
 0(2(0(x1))) -> 1(0(1(x1)))
 L(2(0(x1))) -> L(1(0(1(x1))))
 0(2(R(x1))) -> 1(0(1(R(x1))))

Proof:
 Bounds Processor:
  bound: 1
  enrichment: match
  automaton:
   final states: {5,4,3}
   transitions:
    11(20) -> 21*
    11(7) -> 8*
    01(8) -> 9*
    R1(6) -> 7*
    R1(18) -> 19*
    21(9) -> 10*
    10(2) -> 3*
    10(1) -> 3*
    20(2) -> 1*
    20(1) -> 1*
    00(2) -> 4*
    00(1) -> 4*
    L0(2) -> 5*
    L0(1) -> 5*
    R0(2) -> 2*
    R0(1) -> 2*
    1 -> 18*
    2 -> 6*
    9 -> 20*
    10 -> 3*
    19 -> 7*
    21 -> 4*
  problem:
   
  Qed